o2oa 流程选择界面 无法按人员进行排除

magician

系统版本o2oa 9.0.3
需要实现的是 其中有几个人员需要根据身份 从群组中排除，在指定节点进行流转。（但是这些人员还在原有的群组中需要在别的节点做审批，不能单独建立群组），但是我现在流转下来，群组部分没问题，但是这些指定的人员 无法在正确的节点进行流转，是脚本出问题了么？后台也没有报错。

如下流程图，框选的选择条件，脚本如下
上图 路由 1 ：

var groupList = this.org.listGroupWithPerson(this.workContext.getWork().creatorPersonDn);
var newData = groupList[0].distinguishedName;
var work = this.workContext.getWork().creatorPersonDn;


var yzgyg = "有主管员工@YouZhuGuanYuanGong@G";
var wzgyg = "无主管员工@WuZhuGuanYuanGong@G";
var gbmzg = "各部门主管@GeBuMenZhuGuan@G";
var gbmjl = "各部门经理@GeBuMenJingLi@G";
var gbmzj = "各部门总监@GeBuMenZongJian@G";
var kqzy =  "考勤专员@KaoQinZhuanYuan @G";
var ymzy =  "易茂智一@YiMaoZhiYi@G";

var dyy = "dyy@DuYanYan@P";
var ydf = "ydf@YangDanFeng@P";
var szy = "szy@ShuZhanYi@P";


return work != dyy&&newData == gbmjl||work != ydf&&newData == gbmjl||work != dyy&&newData == gbmzj||work != ydf&&newData == gbmzj||newData == kqzy||(work != szy&&newData == ymzy)&&(parseFloat(this.data.ymzysum)>1)||newData == yzgyg&&parseFloat(this.data.sum)>=2||newData == wzgyg&&(parseFloat(this.data.sum)>=2);



上图 路由 2

var groupList = this.org.listGroupWithPerson(this.workContext.getWork().creatorPersonDn);
var newData = groupList[0].distinguishedName;
var work = this.workContext.getWork().creatorPersonDn;


var yzgyg = "有主管员工@YouZhuGuanYuanGong@G";
var wzgyg = "无主管员工@WuZhuGuanYuanGong@G";
var gbmzg = "各部门主管@GeBuMenZhuGuan@G";
var gbmjl = "各部门经理@GeBuMenJingLi@G";
var gbmzj = "各部门总监@GeBuMenZongJian@G";
var kqzy =  "考勤专员@KaoQinZhuanYuan @G";
var ymzy =  "易茂智一@YiMaoZhiYi@G";

var dyy = "dyy@DuYanYan@P";
var ydf = "ydf@YangDanFeng@P";
var szy = "szy@ShuZhanYi@P";

return newData != gbmjl&&newData != gbmzj&&newData != kqzy&&newData == yzgyg&&(parseFloat(this.data.sum)<2)||newData == wzgyg&&(parseFloat(this.data.sum)<2)||(work != szy&&newData == ymzy)&&(parseFloat(this.data.ymzysum)<=1);




上图 路由3


var groupList = this.org.listGroupWithPerson(this.workContext.getWork().creatorPersonDn);
var newData = groupList[0].distinguishedName;
var work = this.workContext.getWork().creatorPersonDn;


var yzgyg = "有主管员工@YouZhuGuanYuanGong@G";
var wzgyg = "无主管员工@WuZhuGuanYuanGong@G";
var gbmzg = "各部门主管@GeBuMenZhuGuan@G";
var gbmjl = "各部门经理@GeBuMenJingLi@G";
var gbmzj = "各部门总监@GeBuMenZongJian@G";
var kqzy =  "考勤专员@KaoQinZhuanYuan @G";
var ymzy =  "易茂智一@YiMaoZhiYi@G";

var dyy = "dyy@DuYanYan@P";
var ydf = "ydf@YangDanFeng@P";
var szy = "szy@ShuZhanYi@P";


return (work == dyy&&newData != gbmjl)||(work == dyy&&newData != gbmzj)&&newData != kqzy&&newData != yzgyg&&newData != wzgyg&&newData != ymzy;








上图路由 4

var groupList = this.org.listGroupWithPerson(this.workContext.getWork().creatorPersonDn);
var newData = groupList[0].distinguishedName;
var work = this.workContext.getWork().creatorPersonDn;


var yzgyg = "有主管员工@YouZhuGuanYuanGong@G";
var wzgyg = "无主管员工@WuZhuGuanYuanGong@G";
var gbmzg = "各部门主管@GeBuMenZhuGuan@G";
var gbmjl = "各部门经理@GeBuMenJingLi@G";
var gbmzj = "各部门总监@GeBuMenZongJian@G";
var kqzy =  "考勤专员@KaoQinZhuanYuan @G";
var ymzy =  "易茂智一@YiMaoZhiYi@G";

var dyy = "dyy@DuYanYan@P";
var ydf = "ydf@YangDanFeng@P";
var szy = "szy@ShuZhanYi@P";



return work == ydf&&newData != gbmjl||work == ydf&&newData != gbmzj||newData != kqzy&&newData != yzgyg||newData != wzgyg||newData != ymzy;




上图路由 5

var groupList = this.org.listGroupWithPerson(this.workContext.getWork().creatorPersonDn);
var newData = groupList[0].distinguishedName;
// var newData = this.data.add('newData', groupList[0].distinguishedName);
var work = this.workContext.getWork().creatorPersonDn;


var yzgyg = "有主管员工@YouZhuGuanYuanGong@G";
var wzgyg = "无主管员工@WuZhuGuanYuanGong@G";
var gbmzg = "各部门主管@GeBuMenZhuGuan@G";
var gbmjl = "各部门经理@GeBuMenJingLi@G";
var gbmzj = "各部门总监@GeBuMenZongJian@G";
var kqzy =  "考勤专员@KaoQinZhuanYuan @G";
var ymzy =  "易茂智一@YiMaoZhiYi@G";

var dyy = "dyy@DuYanYan@P";
var ydf = "ydf@YangDanFeng@P";
var szy = "szy@ShuZhanYi@P";

return newData != gbmjl||newData != gbmzj||newData != kqzy||newData != yzgyg||newData != wzgyg||work == szy&&newData != ymzy;

论坛管理员

加一些print输出，到日志查看器里看看，您这个描述，看不出来问题